Oblicz ile gramów tlenku fosforu V powstanie z utlenienia 0.1 mola fosforu.
Tlenek fosforu(V) M(P₄O₁₀)=2*31+5*16=142 g/mol 4P + 5O₂ ⇒ 2P₂O₅ 4mole ------- 2 mole 4mole ------ 284g 0,1mola-----x x=7,1g
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Tlenek fosforu(V) M(P₄O₁₀)=2*31+5*16=142 g/mol
4P + 5O₂ ⇒ 2P₂O₅
4mole ------- 2 mole
4mole ------ 284g
0,1mola-----x
x=7,1g