Oblicz mase dwutlenku siarki, który zajmuje objetość 0,03 dm3 w temp. 293K, pod ciśnieniem normalnym (1013hPa)
M(SO₂)=32g/mol+2*16g/mol=64g/mol
V=0,03dm³
T=293K
p=1013hPa
R=83,1hPa*dm³/mol*K
n=?
m=?
pV=nRT /:RT
n=pV/RT
n=1013hPa*0,03dm³ / 83,1hPa*dm³/mol*K * 293K
n=30,39 / 24348,3
n=0,00125mol
n=ms/M /*M
ms=n*M
ms=0,00125mol*64g/mol
ms=0,08g
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M(SO₂)=32g/mol+2*16g/mol=64g/mol
V=0,03dm³
T=293K
p=1013hPa
R=83,1hPa*dm³/mol*K
n=?
m=?
pV=nRT /:RT
n=pV/RT
n=1013hPa*0,03dm³ / 83,1hPa*dm³/mol*K * 293K
n=30,39 / 24348,3
n=0,00125mol
n=ms/M /*M
ms=n*M
ms=0,00125mol*64g/mol
ms=0,08g