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x²=15²+20²
x²=225+400
x²+625 /√
x=25
b=20cm
c=?
a²+b²=c²
15²+20²=c²
225+400=c²
c²=625
c=√625
c=25
d²=225+400
d²=625
d=√625
d=5cm= długośc tej przekatnej