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b=5dm
h=4dm
z pitagorasa
a²+b²=d²
7²+5²=d²
49+25=d²
d=√74 dm --->przekatna podstawy
(√74)²+h²=D²
74+4²=D²
74+16=D²
D=√90=3√10 dm --->dl,przekatnej bryly
sinα=h/D=4/3√10=(4√10)/(3·10)=4√10/30=2√10/15≈0,421 to α=25°