Oblicz delte
x² - 10x - 9
a = 1, b = -10, c = -9
Δ = b² -4ac = (-10)² - 4 * 1 * (-9) = 100 + 36 = 136
Pozdrawiam
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x² - 10x - 9
a = 1, b = -10, c = -9
Δ = b² -4ac = (-10)² - 4 * 1 * (-9) = 100 + 36 = 136
Pozdrawiam