Question

Oblicz delte i x1 i x2
3x kwadrat+1.6x-0.75=0

Answer 1

3x² + 1,6x - 0,75 = 0
Δ = 1,6² - 4 * 3  (-0,75) = 2,56 + 9 = 11,56
√Δ = 3,4
x₁ = (-1,6 -3,4)/6 = -5/6
x₂ = (-1,6 + 3,4)/6 = 3/10
x ∈ {-5/6; 3/10}

Answer 2

Delta=4624
x1=-1,4
x2=52/60