Oblicz deltę z funkcji kwadratowej :
F(x) = 2x2 + 5x – 12
ze wzoru delta= b^2 -4*a*c
delta = 5*5 - 4*2*(-12) = 25 + 96 = 121
a = 2 b = 5 c = -12
Δ = b² - 4ac = 5² - 4 * 2 * (-12) = 25 + 96 = 121
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ze wzoru delta= b^2 -4*a*c
delta = 5*5 - 4*2*(-12) = 25 + 96 = 121
F(x) = 2x2 + 5x – 12
a = 2 b = 5 c = -12
Δ = b² - 4ac = 5² - 4 * 2 * (-12) = 25 + 96 = 121