oblicz całkowitą ilość atomów w 10g NaOH
40g NaOH --- 18,06 x 10 (23) atomów
10g NaOH --- X
X=4,515 x 10 (23) atomów
(23) to potęga 10
M(NaOH)=23g+16g+1g=40g
40g-------------6,02*10²³
10g--------------x
x=10g*6,02*10²³/40g
x=1,505*10²³ cząsteczek
3*1,505*10²³=4,515*10²³ atomów
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40g NaOH --- 18,06 x 10 (23) atomów
10g NaOH --- X
X=4,515 x 10 (23) atomów
(23) to potęga 10
M(NaOH)=23g+16g+1g=40g
40g-------------6,02*10²³
10g--------------x
x=10g*6,02*10²³/40g
x=1,505*10²³ cząsteczek
3*1,505*10²³=4,515*10²³ atomów