120 = 34b - 2b²
-2b² + 34b - 120 = 0
b² - 17b + 60 = 0
Δ = (-17)² - 4*1*60 = 49
√Δ = √49 = 7
b₁ = -(-17) - 7/2*1 = 5
b₂ = -(-17)+7/2*1 = 12
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Litterarum radices amarae sunt, fructus iucundiores
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120 = 34b - 2b² 2b² - 34b + 120 = 0 /:2 b² -17b + 60 = 0 a = 1 b = -17 c = 60 Δ = b² - 4ac = (-17)² - 4 * 1 * 60 = 289 - 240 = 49 √Δ = 7 b1 = (-b - √Δ) / 2a = (17 - 7) / 2 = 10/2 = 5 b2 = (-b + √Δ) / 2a =(17 + 7) / 2 = 24/2 = 12
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120 = 34b - 2b²
-2b² + 34b - 120 = 0
b² - 17b + 60 = 0
Δ = (-17)² - 4*1*60 = 49
√Δ = √49 = 7
b₁ = -(-17) - 7/2*1 = 5
b₂ = -(-17)+7/2*1 = 12
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
120 = 34b - 2b²
2b² - 34b + 120 = 0 /:2
b² -17b + 60 = 0
a = 1 b = -17 c = 60
Δ = b² - 4ac = (-17)² - 4 * 1 * 60 = 289 - 240 = 49
√Δ = 7
b1 = (-b - √Δ) / 2a = (17 - 7) / 2 = 10/2 = 5
b2 = (-b + √Δ) / 2a =(17 + 7) / 2 = 24/2 = 12