a)2·sin²45+7tg30·cos60=2·(√2/2)² +7·√3/3 ·½ =2·½·(7√3)/6 =1·(7√3)/3=2⅓√3
b)(ctg60-tg60)²-(ctg60+tg60)² =(√3/3-√3)²-(√3/3+√3)² =(3/9-2 -3)-(3/9+2+3)=
1/3 -5 -1/3 -5 =-10
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a)2·sin²45+7tg30·cos60=2·(√2/2)² +7·√3/3 ·½ =2·½·(7√3)/6 =1·(7√3)/3=2⅓√3
b)(ctg60-tg60)²-(ctg60+tg60)² =(√3/3-√3)²-(√3/3+√3)² =(3/9-2 -3)-(3/9+2+3)=
1/3 -5 -1/3 -5 =-10