Oblicz
-2(a+b+c)-3(a-b+c)+4(a-b-c) DLA a=-1 b=-2 c=-3
= -2a -2b -2c -3a +3b-3c +4a -4b -4c =
= -a -3b -9c
dla a=-1 b=-2 c=-3
-(-1) -3*(-2) - 9*(-3) =
=1 +6 +27 =
= 34
-2(a+b+c)-3(a-b+c)+4(a-b-c)=-2(-1-2-3)-3(-1+2-3)+4(-1+2+3)=-2(-6)-3(-2)+4(4)=12+6+16=34
-2(a+b+c)-3(a+b+c)+4(a-b-c)=-2a-2b-2c-(-3a)-3b-3c+4a-4b-4c=-1a-9b-9c=
-1*(-1)-9*(-2)-9*(-3)=1+18+27=46
Myślę, że powinno być dobrze. ;P
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Oblicz
-2(a+b+c)-3(a-b+c)+4(a-b-c) DLA a=-1 b=-2 c=-3
= -2a -2b -2c -3a +3b-3c +4a -4b -4c =
= -a -3b -9c
dla a=-1 b=-2 c=-3
-(-1) -3*(-2) - 9*(-3) =
=1 +6 +27 =
= 34
-2(a+b+c)-3(a-b+c)+4(a-b-c)=-2(-1-2-3)-3(-1+2-3)+4(-1+2+3)=-2(-6)-3(-2)+4(4)=12+6+16=34
-2(a+b+c)-3(a+b+c)+4(a-b-c)=-2a-2b-2c-(-3a)-3b-3c+4a-4b-4c=-1a-9b-9c=
-1*(-1)-9*(-2)-9*(-3)=1+18+27=46
Myślę, że powinno być dobrze. ;P