Objętość kuli jest równa 12. Oblicz pole powierzchni tej kuli.
V = 12π
V = 4/3πr³
4/3πr³ = 12π /·3
4πr³ = 36π /: 4
πr³ = 9π /:π
r³ = 9
r = ∛9
P = 4πr²
P = 4 · π · (∛9)²
P = 4 · π · ∛81
P = 4 · π · ∛27 · ∛3
P = 4 · π · 3∛3
P = 12∛3π
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V = 12π
V = 4/3πr³
4/3πr³ = 12π /·3
4πr³ = 36π /: 4
πr³ = 9π /:π
r³ = 9
r = ∛9
P = 4πr²
P = 4 · π · (∛9)²
P = 4 · π · ∛81
P = 4 · π · ∛27 · ∛3
P = 4 · π · 3∛3
P = 12∛3π