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V= 4/3 πr³
POLE POWIERZCHNI KULI
P = 4 πr²
V = 1dm³ = 1000 cm³
1000 = 4/3πr³ |*¾
750 = πr³ | ÷π
r³ = 750/π
r = ∛750/π
P = 4π (∛750/π)²
P = 4π ∛562500/π²
P = 4π∛562500/9,86
P = 4π∛57048,7 cm³
Myślę, że w takiej postaci to możesz zostawić :)