obicz :
a)√121-√162+√200=
b)√72+3√18+√8=
c) (4√3+√12-√75)*√3=
d. (√2-3√3)²=
e.(√5+3√2)*(√5-3√2)=
a)√121-√162+√200= 11 - 9√2 + 10√2 = 11 + √2
b)√72+3√18+√8= 6√2 + 3 * 3√2 + 2√2 = 17√2
c) (4√3+√12-√75)*√3= 4*3 + 6 - 15 = 3
d. (√2-3√3)²= 2 - 6√6 + 9*3 = 29 - 6√6
e.(√5+3√2)*(√5-3√2)= 5 - 9*2 = -13
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a)√121-√162+√200= 11 - 9√2 + 10√2 = 11 + √2
b)√72+3√18+√8= 6√2 + 3 * 3√2 + 2√2 = 17√2
c) (4√3+√12-√75)*√3= 4*3 + 6 - 15 = 3
d. (√2-3√3)²= 2 - 6√6 + 9*3 = 29 - 6√6
e.(√5+3√2)*(√5-3√2)= 5 - 9*2 = -13