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agar memudahkan kita jadikan saja begini
1 , 3 , 5 , 7 , 9 , ... , 99
2 , 3 , 4 , 5 , 6 , ... , 51
50
∑ (2n-1) (n+1) = (2 x 1 - 1) (1+1) + (2x2-1) (2+1) ,, dst
n=1
= (1x2) + (3x3) ,, dst