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(n+3)!/(n+1)! = 20
Maka, dengan berlakunya:
(n+3)! = (n+3)(n+2)(n+1)!
Diperoleh:
[(n+3)(n+2)(n+1)!]/(n+1)! = 20
Menjadi:
(n+3)(n+2) = 20
n²+5n+6 = 20
n²+5n-14 = 0
(n+7)(n-2) = 0
Sepertinya nilai n tidak mungkin negatif.
Diperoleh, n = 2