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C4,3 = 4! / 1! 3!
= 4
C9.3 = 9! / 6! 3!
= 84
peluang= C4,3 / C9,3
⇒⇒⇒⇒⇒ 4/84
⇒⇒⇒⇒⇒1/84
⇒⇒⇒⇒⇒ 1/21
₄C₃ = 4!/3!1! = 4
Dan banyak semesta yang terjadi:
Ada 9 lampu diambil 3.
₉C₃ = 9! / 6! 3! = 9.8.7/3.2 = 84
Maka,
P = n(A)/n(S)
P = 4/84
P = 1/21