Question

No 1 dan 2 Beserta caranya kak...

Answer 1

1)
x^(3m^2 - 5m -2) = 1 = x^0
3x^2 - 5m - 2 = 0
(3x + 1)(x - 2)  = 0
x = - 1/3 atau x = 2

2)
3^x + 9^x = 90
3^x + (3^x)^2 = 90
3^x = a --> x = 3'log a dan a >0

a^2 + a - 90 = 0
(a+10)(a-9) = 0
a = - 10 ( TM) atau a = 9
x = 3'log 9
x = 2

nilai 3^(x-2)= 3^(0)= 1