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Verified answer
-----------Diket :
r = x
dm = (m/L).dx
Krn di putar pada ujung maka batas nya adalah :
X1 = 0 dan x2 = L
Tanya :
Momen inersia pada ujung, I = __?
Jawab :
I = ∫ r².dm
I = ∫ x². (m/L). dx
I = (m/L). ∫ x².dx
I = (m/L). (1/3).x³ [ dng batas x1 = 0 dan x2 = L)
I = (m/L). (1/3).{L³ - 0³}
I = (m/L)•(1/3)•{L³}
I = 1/3•m•L²
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FZA