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f(x)=2x(x²-12)
f⁻¹(x)=2x³-24x
Nilai maksimum
-1≤x≤2
f(x)=2x(x²-12)
f(-1)=2(-1)(-1²-12)
=-2(1-12)
=-2(-11)
=22
f(0)=2(0)(0²-12)
=0(0-12)
=0(-12)
=0
f(1)=2(1)(1²-12)
=2(1-12)
=2(-11)
=-22
f(2)=2(2)(2²-12)
=4(4-12)
=4(-8)
=-32
Nilai maksimum 22
Pilihan A.
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