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b²-4ac=0
(-4)² - 4(1)(k)=0
16 - 4k =0
4k = 16
k = 4
↓→(substitusikan)←↓
x²-4x+k=0
x²-4x+4=0
(x-2)(x-2)=0
x=2 atau x=2 (akar kembar)
aku gk tau knp gk ada di pilihannya.. mohon maaf klau slah