February 2019 1 82 Report
Akar akar persamaan kuadrat (x-3)pangkat 2 - 16 =0 adalah x1 dan x2 .Apabila x1 < x2 maka nilai x1 dan x2 adalah A.x1=-7 dan x2=1 B.x1 =-1 dan x2 =7 C.x1=-7 dan x2=-1 D.x1=1 dan x2 =7

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