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y-ilość żab
2x-nogi bocianów
4y-nogi żab
x+y=21
4y+2x=60
x=21-y
4y+2x=60
x=21-y
4y+2(21-y)=60
x=21-y
4y+42-2y=60
x=21-y
2y=18
y=9
x=12
b - bocian
4z + 2b = 60
z + b = 21
z = 21-b
4*(21-16)+2b = 60
84 - 4b + 2b = 60
-2b = 60-84
2b = 24
b=12
z + 12 = 21
z = 9
Odp: było 9 żab i 12 bocianów
Pozdro :)