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x² + 4x < - 1
x² + 4x + 4 < - 1 + 4
(x + 2)² < 3
x + 2 < √3 dan x + 2 > - √3
x < - 2 + √3 dan x > - 2 - √3
solusi : - 2 - √3 < x < - 2 + √3 ...(A)
7) x² - x - 2 > 0
(x + 1) (x - 2) > 0
x < - 1 atau x > 2
untuk : x < - 1 ambil - 2
=
=
= 4 . 9
= 36 ..... (positif)
untuk x > 2 ,ambil x = 3
=
=
= 9/4 .... positif
kesimpulan .. = POSITIF