Question

Matematika Nomor 4 yang b aja.

Answer 1

Y = sin x / (2 - cos x) = u/v
u = sin x => u' = cos x
v = 2 - cos x => v' = sin x
y' = (u' v - v' u)/v^2 = 0
=> (cos x (2 - cos x) - sin x (sin x)) / (cos x)^2 = 0
=> (2cos x - cos^2 x - sin^2 x) = 0
=> (2 cos x - (cos^2 x + sin^2 x)) = 0
=> (2 cos x - 1) = 0
=> 2cos x = 1
=> cos x = 1/2
x = 60° (kuadran 1) atau x = 300° (kuadran 4)
x = π/3 atau x = 5π/3