1. Podaj wzór sumaryczny i nazwę aldehydu o masie molowej 72g/mol.
CnH2n+1 CHO = 72
12n+2n+1+12+1+16 = 72
14n+30 = 72
14n = 42
n = 3
Wzór: C₃H₇CHO
Nazwa: butanal
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CnH2n+1 CHO = 72
12n+2n+1+12+1+16 = 72
14n+30 = 72
14n = 42
n = 3
Wzór: C₃H₇CHO
Nazwa: butanal