delta Tb=Tb-Tb0
=(100,052-100)°C=0,052°C
delta Tb=m.Kb.i
m=delta Tb/Kb.i
karena i=1+(n-1)
maka m=delta Tb/Kb(1+(n-1))
m=0,052/0,52 (1+(2-1))
=0,052/1,04
=0,05
m=gram /Mr×1000/v
Mr=gram/m×1000/v
=20/0,05×1000/1000
=400×1=400
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delta Tb=Tb-Tb0
=(100,052-100)°C=0,052°C
delta Tb=m.Kb.i
m=delta Tb/Kb.i
karena i=1+(n-1)
maka m=delta Tb/Kb(1+(n-1))
m=0,052/0,52 (1+(2-1))
=0,052/1,04
=0,05
m=gram /Mr×1000/v
Mr=gram/m×1000/v
=20/0,05×1000/1000
=400×1=400
semoga membantu:)
#backtoschool2019