Question

Un compuesto con masa molar de 162,1 g/mol y una composición porcentual de 74,0% de carbono, 8,7% de hidrógeno y 17,3 de nitrógeno es sobre formula molecular

Answer 1

Carbono:

C = 74 g/ 12 g/mol = 6.167 mol
H = 8.7 g/ 1 g/mol = 8.7 mol
O = 17.3 g / 16 g/mol = 1.081 mol

dividir entree el menor de los resultados

C: 6.167 mol / 1.081 mol = 6
H: 8.7 mol / 1.081 mol = 8
O: 1.081 mol / 1.081 mol = 1

FE = C6H6O

Mm FE

C = 6 x 12 = 72 g/mol
H: 6 x 1 = 6 g/mol
O: 1 x 16 = 16 g/mol
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         Mm = 94 g/mol

n= 162.1 g/mol / 94 g/mol = 2

FM = (FE)n

FM = (C6H6O) 2 = C12H12O2