Mohon dibantu no 3 nak mbak!!! #makasih.... Question from @Anandairsyah

Syubbana Tan x = a

3a^2 - 7a + 2 = 0
(3a -1)(a - 2) = 0
3a - 1 = 0 atau a-2 = 0
3a = 1 a = 2 (tdk memenuhi)
a = 1/3

tan x = a
tan x = 1/3
atan 1/3 = 18,4 derajat

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Mujee $\displaystyle 3\tan^2x - 7 \tan x+2=0\\(3\tan x-1)(\tan x-2)=0\\\tan x=\frac{1}{3}\ atau\ x=2\\\\\text{Dari segitiga yang diberikan, kita peroleh:}\\\text{Untuk: }\\\bigstar~~\tan x=\frac{1}{3}\\\\x=18,4^0+k.180^0\\k=0\rightarrow x=18,4^0\\k=1\rightarrowx=18,4^0+180^0=198,4^0\\\\\bigstar~~~\tan x=2\\\\x=63,4^0+k.180^0\\k=0\rightarrow x=63,4^0\\k=1\rightarrow x=63,4^0+180^0=243,4^0\\\\\text{Sehingga:}\\\\\boxed{\bold{Hp=\{18,4^0;~63,4^0;~198,4^0;~243,4^0\}}}$

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