Question

Mohon bantuannya,
Bagaimanakah Cara Mengerjakan nomor 20 dan nomor 21 ?

Answer 1

20.
3x²+7x-6 / 9x²-4
= (3x-2)(x+3) / (3x-2)(3x+2)
= x+3 / 3x+2
[D]

21.
x-5/3 - 2x-7/8
= 8(x-5)-3(2x-7) / 24
= 8x-40-6x+21 / 24
= 2x-19 / 24
[C]

Answer 2

20.) => 3x²+7x-6
3x²+9x-2x-6
3x(x+3)-2(x+3)
(3x-2)(x+3)
=> 9x²-4
(3x-2)(3x+2)
(3x-2)(x+3)
_________
(3x-2)(3x+2)
yg sama dicoret.
Jadi,jwabannya x+3
____
3x+2
21.) x-5 2x-7
___ - ___
3. 8
=>> 8x - 40 - 6x-21
________________
24
8x-6x-40-21
______________
24
2x-61
____________
24