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3a+ b=5
a+b=29
a-3b=5
--------------------kedua ruas dikurangkan\
4b=24
b=24/4
=6
a=3b+5
=3.6+5
=18+5
=23
jadi,nbilangan tsb berturut-turut adalah 23 dan 6(B)
18(.3x²+2x-5)+(2x²-4x+3)
=3x²+2x-5+2x²-4x+3
=3x²+2x²+2x-4x-5+3
=5x²-2x-2(B)
19.(2X+5)(3x-1)
=2x(3x-1)+5(3x-1)
=6x²-2x+15x-5
=6x²+13x-5(A)