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mB = 3 kg
μk = 0,4
a = 2 m/s²
Hukum ke-2 Newton:
∑F = mB.a
F-fk(B thdp lantai)-fk(A thdp B) = mB.a
F- (NAB.μk) - (NBL.μk) = mB.a
F- (50.0,4) - (20.0,4) = 3.2
F = 6 + (50.0,4) + (20.0,4)
= 6 + 20 + 8
= 34 N........opsi D