Miejscami zerowymi funkcji f(x)=-3x^+bx+c sż liczby -5 i 7 . Wyznacz wartości współczynników b i c.
f(x) = - 3 x^2 + b x + c
oraz f( -5) = 0, f(7) = 0
zatem
-3*(-5)^2 - 5 b + c = 0
-3 *7^2 + 7 b + c = 0
-------------------------------
- 75 - 5 b + c = 0
- 147 + 7 b + c = 0
--------------------------- odejmujemy stronami
( - 75 - 5 b + c) - ( - 147 + 7 b + c) = 0
72 - 12 b = 0
12 b = 72
b = 6
------
c = 5 b + 75 = 5*6 + 75 = 30 + 75 = 105
-----------------------------------------------------
Odp. b = 6, c = 105
=====================
f(x) = -3x²+bx+c
f(-5) = 0 i f(7) = 0
-3(-5)²+b(-5)+c = 0
-3·7²+b·7+c = 0
-75-5b+c = 0
-147 +7b+c = 0
-5b+c = 75 I*(-1)
7b+c = 147
5b-c = -75
-------------- +
12b = 72 /:12
====
c = 75+5b = 75+5·6 = 105
c = 105
======
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
f(x) = - 3 x^2 + b x + c
oraz f( -5) = 0, f(7) = 0
zatem
-3*(-5)^2 - 5 b + c = 0
-3 *7^2 + 7 b + c = 0
-------------------------------
- 75 - 5 b + c = 0
- 147 + 7 b + c = 0
--------------------------- odejmujemy stronami
( - 75 - 5 b + c) - ( - 147 + 7 b + c) = 0
72 - 12 b = 0
12 b = 72
b = 6
------
c = 5 b + 75 = 5*6 + 75 = 30 + 75 = 105
-----------------------------------------------------
Odp. b = 6, c = 105
=====================
f(x) = -3x²+bx+c
f(-5) = 0 i f(7) = 0
-3(-5)²+b(-5)+c = 0
-3·7²+b·7+c = 0
-75-5b+c = 0
-147 +7b+c = 0
-5b+c = 75 I*(-1)
7b+c = 147
5b-c = -75
7b+c = 147
-------------- +
12b = 72 /:12
b = 6
====
c = 75+5b = 75+5·6 = 105
c = 105
======