Question

Me ayudan en esto por fa .
(x+1) + (x+2) + (x+3) + .............. + (x+n)=n²

Answer 1

(x+1) + (x+2) + (x+3) + .............. + (x+n)=n²
nx + 1+ 2 + 3 +.......+n = n^2
nx + n*(n+1)/2 = n^2
nx + (n^2+n)/2 = n^2
2nx + n^2 + n = 2n^2
2nx = n^2 - n
2x = n - 1
x = (n - 1)/2

Answer 2

∞Resolver.



Se va "nx" y tambien "n" .


 ← Rpta.