Matma , II gim. Zadanie w zalaczniku ;) Dobra jakosc zdjecia, pilne!
A. 360':12=30' 30'*3=90'
B. 30':5=6' (4*30)-(2*6)= 120'-12'= 108'
c. (1*30') + (3*6')= 48'
1. 360 st. : 12= 30
30*3=90
2. 30: 5=6 st.
4*30 + 3*6= 120+ 18 = 128 st.
3. 30+ 3*6= 30+ 18= 48
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A. 360':12=30' 30'*3=90'
B. 30':5=6' (4*30)-(2*6)= 120'-12'= 108'
c. (1*30') + (3*6')= 48'
1. 360 st. : 12= 30
30*3=90
2. 30: 5=6 st.
4*30 + 3*6= 120+ 18 = 128 st.
3. 30+ 3*6= 30+ 18= 48