Matematyka zadanie w załączniku
a)(1/3)³·(3/4)³=(1/3·3/4)³ =(3/12)³=(1/4)³ =1/64
b)4⁵·(-2,5)⁵=(4· (-2,5)⁵=10⁵=100000
c)(-2)³·(1/2)³·3³= (-2·½·3)³=(-3)³=-27
d)(-10)⁴·(0,01)⁴·50⁴=[(-10·0,01·50)]⁴=(-5)⁴=625
e)(3,3)²·(-2/3)²·(-5)²=[(33/10· (-⅔)·(-5)]² =11²=121
f)1,25⁴/0,25⁴ =(1,25/0,25)⁴=5⁴=625
g)(-4,12)³ :(1,03)³=(-4,12:1,03)³=(-4)³=-64
h)(-2,4)¹⁰ :(2²/₅)¹⁰ =(-2,4:2,4)¹⁰=(-1)¹⁰ =1
i)(0,6)³ :(-0,1)³ =[(0,6: (-0,1)]³ =(-6)³=-216
j)(-25)³ :(-5)³ =5³=125
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
a)(1/3)³·(3/4)³=(1/3·3/4)³ =(3/12)³=(1/4)³ =1/64
b)4⁵·(-2,5)⁵=(4· (-2,5)⁵=10⁵=100000
c)(-2)³·(1/2)³·3³= (-2·½·3)³=(-3)³=-27
d)(-10)⁴·(0,01)⁴·50⁴=[(-10·0,01·50)]⁴=(-5)⁴=625
e)(3,3)²·(-2/3)²·(-5)²=[(33/10· (-⅔)·(-5)]² =11²=121
f)1,25⁴/0,25⁴ =(1,25/0,25)⁴=5⁴=625
g)(-4,12)³ :(1,03)³=(-4,12:1,03)³=(-4)³=-64
h)(-2,4)¹⁰ :(2²/₅)¹⁰ =(-2,4:2,4)¹⁰=(-1)¹⁰ =1
i)(0,6)³ :(-0,1)³ =[(0,6: (-0,1)]³ =(-6)³=-216
j)(-25)³ :(-5)³ =5³=125