Matematyka z plusem 2 str. 80 zad. 11 *
Pole trapezu o podstawach x i y jest równe xy+y^. Jaka jest wysokość tego trapezu?
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zad.11
P=(x+y)*h /2
xy+y^2=(X+y)*h /2
xy+y^2=hx+hy /2
xy+y^2=h(x+y) /2 /*2
2xy+2y^2=h(x+y) /:(x+y)
(2xy+2y^2)/(x+y)=h
P=(x+y)*h /2
xy+y^2=(X+y)*h /2
xy+y^2=hx+hy /2
xy+y^2=h(x+y) /2 /*2
2xy+2y^2=h(x+y) /:(x+y)