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Jawab4. f(x) = (2x² + 4) /(√x)
f(x)= (2x² + 4)(x^(-1/2))
f(x) = 2x^(3/2) + 4 x^(-1/2)
f'(x) = 3/2 (2) x^(1/2) - 2 x^(-3/2)
f'(x) = 3 √x - 2/(x√x)
f'(x) = (3 √x - (2√x)/(x²)
f'(x) = (3 - 2/x²) √x
5) f(x) = 8 (2x³ -5)^(1/2)
f'(x) = 8(1/2) (6x²) /(2x³ -5)^(1/2)
f'(x) = (24 x²) / √(2x³-5)