January 2019 1 7 Report
Mam takie zadania, proszę o pokazanie obliczeń, dużo punktów dam!
(- 2^{3} ) ^{3} : 4 ^{3} * \frac{1}{4 ^{3} } =

 -\frac{3}{4} : \frac{1-(- \frac{1}{2}) ^{4} }{1-(- \frac{1}{2}) } =

 \frac{1 \frac{1}{2} * (2 ^{2}) ^{2} }{32} =

 \left \{ {{x-y=0} \atop {2x+5y=7}} \right.

 \left \{ {{x+2y=5} \atop {2x+5y=-8}} \right.

 \sqrt{2}( \sqrt{32} - \sqrt{50} + \sqrt{8} ) =

 \sqrt[3]{27} - \sqrt[3]{32} - \sqrt[3]{125}

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.