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k = 1600 N/m
Δx = 5 cm → 0,05 m
kp = 3(1600 N/m) → 4800 N/m
1/ktotal = 1/1600 + 1/4800 → 4/4800
ktotal = 4800/4 → 1200 N/m
ditanya :
F/W = ...?
jawab :
F = k Δx
F = 1200 (0,05)
F = 60 N