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an = a1 + (n - 1)*d
Donde a1 = 600; n = 15; d = 20
an = a15
a15 = 600 + (15 - 1)*(20)
a15 = 600 + (14)(20)
a15 = 600 + 280
a15 = 880
Rta: El ultimo dia de la quincena recorre 880 m