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= (-1 - 0 , 0 - 1 , 2 - -2)
= (-1 , -1 , 4)
panjang AB =
=
= √18
= 3√2
vektor AC = c - a
= (-1 - 0 , -1 - 1 , 0 - -2)
= (-1 , -2 , 2)
panjang AC =
=
= √9
= 3
sudut antara vektor AB dan AC (sudut BAC)
cos BAC =
=
=
=
sudut BAC =
L.ΔABC = . AB . AC .sin BAC
= . 3√2 . 3 .sin
= .
= . 2
=
= 4,5 satuan luas