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b = (1+√3)² / (-2)
a+b = [(1-√3)² + (1+√3)²] / (-2)
a+b = 2+6= 8
.
2)
= 2'log 48 - 2'log 3 + ( 5'log 50 - 5'log 2)
= 2'log 16 + 5'log 25
= 2'log 2^4 + 5'log 5^2
= 4 + 2 = 6
.
3) log 125 = log 5^3 = 3 (log 5)= 3(0,699) = 2,097
.
4) 2'log 8 = 3 --> 2'log√8 =1/2. 2'log 8 = 3/2
2'log 2 = 1 --> 2'log √2 = 1/2 (2'log 2) = 1/2
(3^2- 1^2) / ( (3/2)^2 - (1/2)^2)
= (8)/(9/4 - 1/4)
= 8/2 = 4