Aplicando propiedades operacionales de otencis
36 = 2^2x3^2
log36 = x
= log(2^2x3^2)
= log2^2 + log3^2
= 2log2 + 2log3
= 2(m) + 2(n)
x = 2(m + n) respuesta
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Entonces
Aplicando propiedades operacionales de otencis
36 = 2^2x3^2
log36 = x
= log(2^2x3^2)
= log2^2 + log3^2
= 2log2 + 2log3
= 2(m) + 2(n)
x = 2(m + n) respuesta