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Ketinggian maksimum apabila h' = 0
Sehingga:
h' = 10 - 100t
0 = 10 - 100t
10 = 100t
t = 1/10 detik
Maka, dengan substitusi t = 1/10
h = 10(1/10) - 50(1/10)²
h = 1 - 50(0,01)
h = 1 - 0,5
h = 0,5 meter