liczby zespolone
z^3 = 1 , a wiec z=1^(1/3),
korzystamy z:
1^(1/3) = cos[(0 + 2πk)/3] + i sin[(0 + 2πk)/3] , dla k = 0, 1, 2
i amsz, ze dla k=0:
z = cos(0) + i sin(0) = 1
dalej chyba umiesz ;p
p.s
to do liceum znow wrocily liczby zespolone? :D
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z^3 = 1 , a wiec z=1^(1/3),
korzystamy z:
1^(1/3) = cos[(0 + 2πk)/3] + i sin[(0 + 2πk)/3] , dla k = 0, 1, 2
i amsz, ze dla k=0:
z = cos(0) + i sin(0) = 1
dalej chyba umiesz ;p
p.s
to do liceum znow wrocily liczby zespolone? :D