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2α = 3α - 20 = β + 10
igualando el 1ro y el 2do
2α = 3α - 20
20 = 3α - 2α
20 = α
igualando el 1ro y el 3ro
2α = β + 10
2(20) = β + 10
40 = β + 10
40 - 10 = β
30 = β
entonces se tiene que α + β = 20 + 30 = 50