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pole
P= πr²
a=2cm
r=a/2
P=π * (2cm : 2)= π * 1cm= π cm²
obwód
l = 2πr
r = 2cm
l = 2 * π * 2 cm= 4π cm
b) opisanego
pole
P= πR²
R= 1/2(a√2)= 1/2 * 2√2 cm= √2 cm
P= π * √2 cm= √2πcm²
obwód
l= 2πR
R= √2 cm
l= 2 * π * √2 cm = 2√2π cm