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4/3 π r³
4/3 π 3³
4/3 π 27
V=36
Objętość stożka (36)
V=1/3 π r²
36=1/3 π 4²×H
36=1/3π16×H
36/1×3/1×1/16=H
H=6,75
36=16*1/3h
36=5,1/3h /:5,1/3
6,75=h-tadam