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b).20⁻¹ ·10² = (1/20)¹ ·100 =1/20·100=5
c).(0,2)⁻¹·10= (2/10)⁻¹ ·10 = (1/5)⁻¹ ·10 = 5¹ ·10 = 5·10=50
d).10² :(0,02)⁻¹ = 100:(2/100)⁻¹ = 100:(1/50)⁻¹ = 100:50¹ = 100:50 = 2